Optimal. Leaf size=89 \[ \frac{x \sqrt{a+b x^2} (4 A b-3 a B)}{8 b^2}-\frac{a (4 A b-3 a B) \tanh ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a+b x^2}}\right )}{8 b^{5/2}}+\frac{B x^3 \sqrt{a+b x^2}}{4 b} \]
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Rubi [A] time = 0.035899, antiderivative size = 89, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 4, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.182, Rules used = {459, 321, 217, 206} \[ \frac{x \sqrt{a+b x^2} (4 A b-3 a B)}{8 b^2}-\frac{a (4 A b-3 a B) \tanh ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a+b x^2}}\right )}{8 b^{5/2}}+\frac{B x^3 \sqrt{a+b x^2}}{4 b} \]
Antiderivative was successfully verified.
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Rule 459
Rule 321
Rule 217
Rule 206
Rubi steps
\begin{align*} \int \frac{x^2 \left (A+B x^2\right )}{\sqrt{a+b x^2}} \, dx &=\frac{B x^3 \sqrt{a+b x^2}}{4 b}-\frac{(-4 A b+3 a B) \int \frac{x^2}{\sqrt{a+b x^2}} \, dx}{4 b}\\ &=\frac{(4 A b-3 a B) x \sqrt{a+b x^2}}{8 b^2}+\frac{B x^3 \sqrt{a+b x^2}}{4 b}-\frac{(a (4 A b-3 a B)) \int \frac{1}{\sqrt{a+b x^2}} \, dx}{8 b^2}\\ &=\frac{(4 A b-3 a B) x \sqrt{a+b x^2}}{8 b^2}+\frac{B x^3 \sqrt{a+b x^2}}{4 b}-\frac{(a (4 A b-3 a B)) \operatorname{Subst}\left (\int \frac{1}{1-b x^2} \, dx,x,\frac{x}{\sqrt{a+b x^2}}\right )}{8 b^2}\\ &=\frac{(4 A b-3 a B) x \sqrt{a+b x^2}}{8 b^2}+\frac{B x^3 \sqrt{a+b x^2}}{4 b}-\frac{a (4 A b-3 a B) \tanh ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a+b x^2}}\right )}{8 b^{5/2}}\\ \end{align*}
Mathematica [A] time = 0.0560067, size = 74, normalized size = 0.83 \[ \frac{\sqrt{b} x \sqrt{a+b x^2} \left (-3 a B+4 A b+2 b B x^2\right )+a (3 a B-4 A b) \tanh ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a+b x^2}}\right )}{8 b^{5/2}} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.008, size = 101, normalized size = 1.1 \begin{align*}{\frac{{x}^{3}B}{4\,b}\sqrt{b{x}^{2}+a}}-{\frac{3\,Bax}{8\,{b}^{2}}\sqrt{b{x}^{2}+a}}+{\frac{3\,{a}^{2}B}{8}\ln \left ( x\sqrt{b}+\sqrt{b{x}^{2}+a} \right ){b}^{-{\frac{5}{2}}}}+{\frac{Ax}{2\,b}\sqrt{b{x}^{2}+a}}-{\frac{Aa}{2}\ln \left ( x\sqrt{b}+\sqrt{b{x}^{2}+a} \right ){b}^{-{\frac{3}{2}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.62787, size = 382, normalized size = 4.29 \begin{align*} \left [-\frac{{\left (3 \, B a^{2} - 4 \, A a b\right )} \sqrt{b} \log \left (-2 \, b x^{2} + 2 \, \sqrt{b x^{2} + a} \sqrt{b} x - a\right ) - 2 \,{\left (2 \, B b^{2} x^{3} -{\left (3 \, B a b - 4 \, A b^{2}\right )} x\right )} \sqrt{b x^{2} + a}}{16 \, b^{3}}, -\frac{{\left (3 \, B a^{2} - 4 \, A a b\right )} \sqrt{-b} \arctan \left (\frac{\sqrt{-b} x}{\sqrt{b x^{2} + a}}\right ) -{\left (2 \, B b^{2} x^{3} -{\left (3 \, B a b - 4 \, A b^{2}\right )} x\right )} \sqrt{b x^{2} + a}}{8 \, b^{3}}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 6.03696, size = 150, normalized size = 1.69 \begin{align*} \frac{A \sqrt{a} x \sqrt{1 + \frac{b x^{2}}{a}}}{2 b} - \frac{A a \operatorname{asinh}{\left (\frac{\sqrt{b} x}{\sqrt{a}} \right )}}{2 b^{\frac{3}{2}}} - \frac{3 B a^{\frac{3}{2}} x}{8 b^{2} \sqrt{1 + \frac{b x^{2}}{a}}} - \frac{B \sqrt{a} x^{3}}{8 b \sqrt{1 + \frac{b x^{2}}{a}}} + \frac{3 B a^{2} \operatorname{asinh}{\left (\frac{\sqrt{b} x}{\sqrt{a}} \right )}}{8 b^{\frac{5}{2}}} + \frac{B x^{5}}{4 \sqrt{a} \sqrt{1 + \frac{b x^{2}}{a}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.13256, size = 101, normalized size = 1.13 \begin{align*} \frac{1}{8} \, \sqrt{b x^{2} + a}{\left (\frac{2 \, B x^{2}}{b} - \frac{3 \, B a b - 4 \, A b^{2}}{b^{3}}\right )} x - \frac{{\left (3 \, B a^{2} - 4 \, A a b\right )} \log \left ({\left | -\sqrt{b} x + \sqrt{b x^{2} + a} \right |}\right )}{8 \, b^{\frac{5}{2}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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